Can I achieved to convert double to String and remove all trailing zero behind the point value?

Question

I have looking for the solution around and doing a little workaround here, but can not wrap up all to meet my expectations. For example I have double value as below

double x = 101.00000
double y = 102.02000
double z = 103.20000
double k = 104.30020

I want all the value to become String with the smallest number of decimal they have to show. Expected result

String l = "101"
String m = "102.02"
String n = "103.2"
String o = "104.3002"
// and the l = formatted x, m = formatted y, n = formatted z, o = formatted k

can this be achieved in any way?

Thank you

(Note: someone have suggest my question may duplicate with remove trailing zero in java. But I suggest it's different because in my question the base value is double not String)

Answer 1

Hope this helps:

public static String format(double val) {
     if(val == (long)val) 
          return String.format("%d", (long) val);
     else
          return String.format("%s", val);
}

Input:

1. 101.00000
2. 102.02000

Output:

1. 101
2. 102.02

Answer 2

CONVERT DOUBLE TO STRING

In Java, if you want to convert a value type to another, you should see this 'another type' class and try to find a converting method.

I this case you want to convert a Double type to String. String class has a method called String.valueOf(double d) that changes the number value to String. It also can convert other number types to String thanks to the overload properties.

---

REMOVING UNNECESSARY ZERO

Once you have the String values, use this code with each one to remove the unnecessary zeros.

s = s.indexOf(".") < 0 ? s : s.replaceAll("0*$", "").replaceAll("\\.$", "");

---

In your case:

Double x = 101.00000;
Double y = 102.02000;
Double z = 103.20000;
Double k = 104.30020;

String l = String.valueOf(x);
String m = String.valueOf(y);
String n = String.valueOf(z);
String o = String.valueOf(k);

l = l.indexOf(".") < 0 ? l : l.replaceAll("0*$", "").replaceAll("\\.$", "");
m = m.indexOf(".") < 0 ? m : m.replaceAll("0*$", "").replaceAll("\\.$", "");
n = n.indexOf(".") < 0 ? n : n.replaceAll("0*$", "").replaceAll("\\.$", "");
o = o.indexOf(".") < 0 ? o : o.replaceAll("0*$", "").replaceAll("\\.$", "");

Output:

• 101
• 102.02
• 103.2
• 104.3002