count distinct gmail addresses

Question

need to count distinct gmail addresses provided by user as input, here are the conditions:

not case sensitive:

"a@gmail.com" == "A@GmaiL.com"

The '.' character in the string in the local name is ignored:

"aa@gmail.com" == "a.a@gmail.com"

Gmail domain is same as googlemail

"aa@gmail.com" == "aa@googlemail.com"

my issue is with the very last one. How to implement the last condition in my code?

distinct_emails=[]
email = []
count=0
 for i in range(int(input())):
  item = input().lower().replace(".","")
  email.append(item)

 for i in email:
  if i not in distinct_emails:
    count = count + 1
    distinct_emails.append(i)
print(count)

Answer 1

You could try something like this, where for gmail and googlemail addresses, you check for the swapped versions before appending it to the distinct_emails list.

distinct_emails=[]
email = []
count=0
 for i in range(int(input())):
  item = e.lower()
  # don't remove `.` after the `@`.
  parts = item.split("@")
  email.append(parts[0].replace(".", "") + "@" + parts[1])

for i in email:
  # consider googlemail and gmail to be equivalent
  if not any(e in distinct_emails for e in [i, i.replace('@googlemail.com', '@gmail.com'), i.replace('@gmail.com', '@googlemail.com')]):
    count = count + 1
    distinct_emails.append(i)
print(count)