For instance, if I sorted:
{3:4, 4:5, 5:5, 7:2}
I would expect:
{7:2, 3:4, 4:5, 5:5}
Note: This is not a duplicate of other 'how to sort a dictionary' questions because they do not show how to use the key as a tie-breaker.
Related:
You can sort d.items()
. Since it's key-value tuples, the second elements are values and first elements are keys.
out = dict(sorted(d.items(), key=lambda x: (x[1], x[0])))
Output:
{7: 2, 3: 4, 4: 5, 5: 5}
If the keys are already in order, you can leverage the fact that Python's sort is stable (keeps original order for same value sort key):
{k:d[k] for k in sorted(d,key=d.get)}
{7: 2, 3: 4, 4: 5, 5: 5}
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