PHP Mysql Search and Update in nested JSON cloumn

Question

I have Table by name "centers" column by name "teams":

Schema (MySQL v5.7)

DROP TABLE IF EXISTS `Centers`;

CREATE TABLE IF NOT EXISTS `Centers` (
`id` int(11) NOT NULL ,
`name` VARCHAR(255)  NOT NULL ,
`teams` JSON NOT NULL 
);

INSERT INTO `Centers`
  (`id`, `name`, `teams`)
VALUES
  ('1','Texas','{"teams0":{"name":"Alex","training":"worker","agenda":"https:\/\/example.com\/booking\/alex","terminland_days":"0"},"teams1":{"name":"thomas","training":"worker","agenda":"https:\/\/example.com\/booking\/thomas","terminland_days":"0"}}'),
  ('2','California','{"teams0":{"name":"Dean","training":"worker","agenda":"https:\/\/example.com\/booking\/dean","terminland_days":"0"},"teams1":{"name":"Rose","training":"worker","agenda":"https:\/\/example.com\/booking\/rose","terminland_days":"0"}}');

---

Query #1

SELECT VERSION();

VERSION()
5.7.22

---

Query #2

SELECT `id`, `Name`, `teams`
FROM `Centers`;

id	Name	teams
1	Texas	{"teams0": {"name": "Alex", "agenda": "https://example.com/booking/alex", "training": "worker", "terminland_days": "0"}, "teams1": {"name": "thomas", "agenda": "https://example.com/booking/thomas", "training": "worker", "terminland_days": "0"}}
2	California	{"teams0": {"name": "Dean", "agenda": "https://example.com/booking/dean", "training": "worker", "terminland_days": "0"}, "teams1": {"name": "Rose", "agenda": "https://example.com/booking/rose", "training": "worker", "terminland_days": "0"}}

---

View on DB Fiddle

also I have a Function for get "agenda" value then return "terminland_days":

function get_single_agents_info($url)
{
$arr = explode('/', $url);
$center_slug = $arr[count($arr) - 2];
$agent_slug = $arr[count($arr) - 1];

$data = array("key" => "11111", "request" => "get_agents_info","office_seo_url" =>$center_slug,"agent_seo_url"=>$agent_slug);
$json = json_encode($data);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'https://example.com/booking');
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json'));
curl_setopt($ch, CURLOPT_USERAGENT, 'Atlantomed API');
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $json);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$answer = curl_exec($ch);
curl_close($ch);

$json_answer = json_decode($answer);

if ($json_answer->status == 'OK') {
    foreach ($json_answer->agents as $agent) {
        foreach ($agent->offices as $office) {
            return $office;
            /* print_r ($office);
            result =====>   [next_appointments] => Array ( [0] => stdClass Object ( [remaining_days] => 3 ))   */
        }
    }
}
return null;
}

so in final, I must get "Agenda url" from database and send it to Function, then updating teams column by function return object.

this my wrong php code:

$servername = "localhost";
$username = "root";
$password = "";
$dbname = "sql";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}

$sql = 'SELECT * FROM Centers WHERE teams LIKE "%example.com%"'; /* this wrong */
/* i need select `agenda` in json column */  

$result = $conn->query($sql);
if ($result->num_rows > 0) {
while ($row = $result->fetch_assoc()) {

    $url = $row['agenda'];
    $agents_data = get_single_agents_info($url);
    $next_appointments = !empty($agents_data->next_appointments)  ? $agents_data->next_appointments[0] : [];

if (!empty($next_appointments)) {
        $terminland_date = $next_appointments->date;
        $terminland_days = $next_appointments->remaining_days;
        $updatesql = "UPDATE `Centers` SET `terminland_days` = '" . $terminland_days . "' WHERE `agenda` = '" . $row['agenda'] . "'";
        $conn->query($updatesql);
   }
  }
 }

Question : how can update JSON Column teams in mysql?

Answer 1

I must get "Agenda url" from database and send it to Function

SELECT id, 
       name, 
       CAST(object_name AS CHAR) object_name,
       CAST(JSON_EXTRACT(teams, CONCAT('$.', object_name, '.name')) AS CHAR) name, 
       CAST(JSON_EXTRACT(teams, CONCAT('$.', object_name, '.agenda')) AS CHAR) agenda, 
       CAST(JSON_EXTRACT(teams, CONCAT('$.', object_name, '.training')) AS CHAR) training, 
       CAST(JSON_EXTRACT(teams, CONCAT('$.', object_name, '.terminland_days')) AS CHAR) terminland_days
FROM Centers
JOIN ( SELECT id, JSON_EXTRACT(JSON_KEYS(teams), CONCAT('$[', n, ']')) object_name
       FROM Centers
       JOIN ( SELECT 0 n UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION 
              SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 ) numbers
            ON n < JSON_LENGTH(JSON_KEYS(teams))) paths USING (id)

fiddle with steps description.

Obtained values should be provided into your function.

then updating teams column by function return object.

Then use id , object_name and the value returned by the function and update JSON value using JSON_SET() function.

PS. CAST(.. AS CHAR) is added because the returned value datatype is binary string, and it is displayes in HEX codes. Maybe in your code they should be excess - remove them in this case. Also you may add JSON_UNQUOTE() if needed.