How to search the full string in file which is passed as argument in shell script?

Question

i am passing a argument and that argument i have to match in file and extract the information. Could you please how I can get it?

Example:

I have below details in file-

iMedical_Refined_load_Procs_task_id=970113
HV_Rawlayer_Execution_Process=988835
iMedical_HV_Refined_Load=988836
DHS_RawLayer_Execution_Process=988833
iMedical_DHS_Refined_Load=988834

If I am passing 'hv' as argument so it should to pick 'iMedical_HV_Refined_Load' and give the result - '988836'

If I am passing 'dhs' so it should pick - 'iMedical_DHS_Refined_Load' and give the result = '988834'

I tried below logic but its not giving the result correctly. What Changes I need to do-

echo $1 | tr a-z A-Z
g=${1^^}
echo $g
echo $1
val=$(awk -F= -v s="$g" '$g ~ s{print $2}' /medaff/Scripts/Aggrify/sltconfig.cfg)
echo "TASK ID is $val"

Answer 1

Assuming your matching criteria is the first string after delimiter _ and the output needed is the numbers after the = char, then you can try this sed

$ sed -n "/_$1/I{s/[^=]*=\(.*\)/\1/p}" input_file

$ read -r input
hv
$ sed -n "/_$input/I{s/[^=]*=\(.*\)/\1/p}" input_file
988836

$ read -r input
dhs
$ sed -n "/_$input/I{s/[^=]*=\(.*\)/\1/p}" input_file
988834

Answer 2

If I'm reading it right, 2 quick versions -

$: cat 1
awk -F= -v s="_${1^^}_" '$1~s{print $2}' file

$: cat 2
sed -En "/_${1^^}_/{s/^.*=//;p;}" file

Both basically the same logic.

In pure bash -

$: cat 3
while IFS='=' read key val; do [[ "$key" =~ "_${1^^}_" ]] && echo "$val"; done < file

That's a lot less efficient, though.

If you know for sure there will be only one hit, all these could be improved a bit by short-circuit exits, but on such a small sample it won't matter at all. If you have a larger dataset to read, then I strongly suggest you formalize your specs better than "in this set I should get...".