This question is a follow up on Here . The goal was to implement a virtual equal operator between non templated classes. In this question, I am asking for the same goal for a templated class.
#define EQUAL_FOR_BASE(derived) virtual bool equal(const derived& eq) const { return false; };
#define EQUAL_FOR_DERIVED(this_derived) bool equal(const Equalable& equalable) const { return equalable.equal(*this_derived); };
class RandomClass; //This is for clarification purposes, not used.
class DerivedTemplateType_One;
class DerivedTemplateType_Two;
class Equalable
{
public:
Equalable() = default;
virtual ~Equalable() = default;
virtual bool operator==(const Equalable& eq) { return this->equal(eq); };
EQUAL_FOR_BASE(RandomClass);
EQUAL_FOR_BASE(DerivedTemplateType_One);
EQUAL_FOR_BASE(DerivedTemplateType_Two);
virtual bool equal(const Equalable& eq) const = 0;
};
class RandomClass : public Equalable
{
public:
RandomClass() = default;
~RandomClass() = default;
EQUAL_FOR_DERIVED(this);
virtual bool equal(const RandomClass& rc) const { return m_double == rc.m_double; };
double m_double;
};
class TemplateType : public Equalable //Still pure virtual due to equal in Equalable.
{
public:
TemplateType() = default;
virtual ~TemplateType() = default;
int m_string;
};
class DerivedTemplateType_One : public TemplateType
{
public:
EQUAL_FOR_DERIVED(this);
virtual bool equal(const DerivedTemplateType_One& one) const { return m_int == one.m_int; };
int m_int;
};
class DerivedTemplateType_Two : public TemplateType
{
public:
EQUAL_FOR_DERIVED(this);
virtual bool equal(const DerivedTemplateType_Two& two) const { return m_size == two.m_size; };
std::size_t m_size;
};
template<typename T>
class Target : Equalable
{
public:
T m_t;
};
Q1 : I want to limit the template typename T above to be a derived class of TemplateType (derived from Equalable) eg Can be DerivedTemplateType_One/Two (Of course there will be Three, Four..)? Isn't there static_assert or some metaprogramming to check this at compile time or would:
template<TemplateType DerivedTypeOneOrTwo>
class Target : public Equalable
{
public:
DerivedTypeOneOrTwo m_t;
};
Work?
Q2 : How can I implement the equal operator as I did for RandomClass please?
Q3 : I am asking about Q1 in order to limit template types possible so that Q2 is possible, can I generalize Q1: Limit template typename T to classes inheriting from Equalable (instead of TemplateType ) and still do Q2?
Sorry this is getting a bit complicated but there is no easy way:) Thanks very much!!
Ps: I am making everything public to save space, please ignore.
I ended using CRTP if anyone is interested (Please let me know if I am doing something wrong I missed)
template<class Derived>
class Equalable
{
public:
using derived_type = Derived;
bool operator==(const Derived& derived) const { return this->equal(derived); };
bool operator!=(const Derived& derived) const { return !(*this == derived); }
private:
virtual bool equal(const Derived& derived) const = 0;
};
class B : public Equalable<B>
{
public:
B(double d) : m_example(d) {};
private:
virtual bool equal(const B& derived) const override { return derived.m_example == m_example; };
double m_example;
};
class A : public Equalable<A>
{
public:
A(std::string d) : m_example(d) {};
private:
virtual bool equal(const A& derived) const override { return derived.m_example == m_example; };
std::string m_example;
};
Now we can compare element of same type:
int main()
{
A a("string");
B b(1);
A aa("other_string");
B bb(11);
std::cout << (a == aa) << std::endl; //Ok
std::cout << (b == bb) << std::endl; //Ok
std::cout << (a == b) << std::endl; //Wrong, not supported.
};
I tried doing this:
template<class A, class B>
static bool equal(const Equalable<A>& a, const Equalable<B>& b)
{
if (!std::is_same<A, B>::value)
return false;
return a == b;
};
But didn't compile, so I just used equality between same types.
To limit template (As of Question Q1) there a standard check:
static_assert(std::is_base_of<Base, Derived>::value, "Only from Base");
Hope you have better suggestions, I still don't like this:) Thanks everyone!
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