I have a string.
Input let s = aaabccddd
I want to convert this string to key-> value pairs in an obj.
output let obj = { a:3, b:1, c:2, d:3 }
I know how to make keys but confuse about the value please give a javascript solution thankyou
Just loop over the string and increment a counter in a seperate object for each character.
function countOccurences(string) {
const result = {};
for (const character of string) {
if (typeof result[character] === 'undefined') {
result[character] = 0;
}
result[character]++;
}
return result;
}
console.log(countOccurences('aaabccddd'));
//=> {a: 3, b: 1, c: 2, d: 3}
You can use Function.prototype.call to invoke the Array.prototype.reduce method on the string and group the characters by their occurrences.
const str = "aaabccddd", res = Array.prototype.reduce.call( str, (r, s) => { r[s] ??= 0; r[s] += 1; return r; }, {} ); console.log(res);
Other relevant documentations:
This can be done with Array.reduce()
as follows:
let s = 'aaabccddd'; let result = [...s].reduce((o, c) => { o[c] = (o[c] | 0) + 1; return o; }, {}); console.log(result);
You can use String.match()
with RegExp to get the repeated occurrences of each character, map them toan array of [character, occurrences]
pairs, and convert the list of pairs to an object using Object.fromEntries()
:
const fn = s => Object.fromEntries(s .match(/(.)\1*/g) // find all recuring matches .map(str => [str[0], str.length]) // create an array of [character, occurrences] ) const s = 'aaabccddd' const result = fn(s) console.log(result)
Or use String.matchAll()
with Array.from()
to create the list of entries:
const fn = s => Object.fromEntries( Array.from( s.matchAll(/(.)\1*/g), // find all recuring matches ([{ length }, c]) => [c, length] // create an array of [character, occurrences] ) ) const s = 'aaabccddd' const result = fn(s) console.log(result)
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