Filter array of objects by property with array of strings with an array of strings

Question

So I have data that looks like this:

    const data = [
      { foo: ["0001|main|0002", "0001|main|0014", "0001|main|0016"] },
      { foo: ["0001|main|0014", "0001|main|0018", "0001|main|0019"] },
      { foo: []},
      { foo: ["0001|main|0001", "0001|main|0012", "0001|main|0022"] },
    ];

And I need to filter it with an array of strings that looks like this:

let selections = ["0014", "0016"];

I need to match the items with the same last for numbers only in the data, I currently have this which sort of works:

data.filter((item) => {
 if(!item.foo.length) return false;
 return selections.every((id) => item.foo.split('|')[2] === id)
});

The issue I'm having that when selecting two IDs like above it returns nothing. I was expecting the return value to be this:

[
 {foo: ["0001|main|0002", "0001|main|0014", "0001|main|0016"]},
 {foo: ["0001|main|0014", "0001|main|0018", "0001|main|0019"]},
]

I works fine when selection has only one string in it. I think its searching for items that match both strings in the selection.

Any help would be appreciated!

Answer 1

Since you want

["0001|main|0014", "0001|main|0018", "0001|main|0019"]

to be included, it sounds like you need at least one of the selections to match, rather than every selection to have a match. So, use .some instead of .every .

 const data = [ { foo: ["0001|main|0002", "0001|main|0014", "0001|main|0016"] }, { foo: ["0001|main|0014", "0001|main|0018", "0001|main|0019"] }, { foo: []}, { foo: ["0001|main|0001", "0001|main|0012", "0001|main|0022"] }, ]; const selections = ["0014", "0016"]; const result = data.filter( ({ foo }) => selections.some( sel => foo.some( str => str.endsWith(sel) ) ) ); console.log(result);

Answer 2

The problem with your current solution is you are trying to use the split() method on an array and the split method is intended for strings.

I am sure there may be cleaner ways to approach this issue but here is what I came up with quickly.

You will have to first iterate through your data array, then iterate over each of item.foo's children elements. This then allows you to run a similar check to what you were doing just as a ternary operation instead that will push all the desired items to a dummy array which can then be returned as the result.

 const data = [{ foo: ["0001|main|0002", "0001|main|0014", "0001|main|0016"] }, { foo: ["0001|main|0014", "0001|main|0018", "0001|main|0019"] }, { foo: [] }, { foo: ["0001|main|0001", "0001|main|0012", "0001|main|0022"] }, ]; let selections = ["0014", "0016"]; const filteredItems = []; data.forEach((item) => { item.foo.forEach(fooItem => { if (!fooItem.length) return false; selections.every((id) => fooItem.split('|')[2] === id ? filteredItems.push(item.foo) : false); }) }); console.log(filteredItems)