How do i make a 5 letter username a requirement?

Question

I have this code:

username=input("input username= ")
to_deny = ["!", "?", " ", "/", ",", ".", "[", "]", "(", ")",]
if any([char in username for char in to_deny]):
    print("denied characters: ?, !, space(s), /, dots, [], ()")
    quit()
else:
    print("hello",username,"!")

How can I make it so that the username must contain exactly 5 letters?

Answer 1

if any([char in username for char in to_deny]):
    print("denied characters: ?, !, space(s), /, dots, [], ()")
    quit()
elif len(username) != 5:
    print("username must be 5 characters")
    quit()
else:
    print("hello",username,"!")

Answer 2

I recommend you to use regex, it's really powerful and can be useful to know for harder requirements (eg : email validation, phone number validation, website validation)

import re

regex_condition = r"^[^!? \/,.[\]()]{5}$"
my_string = "aaaaa"

if (re.search(regex_condition, my_string)):
    print("String checked")

1. ^ mean start of the string
2. [^!? \/,.[\]()] [^!? \/,.[\]()] mean a single character NOT in !? \/,.[\]() !? \/,.[\]()
3. {5} mean match the previous token (the single character not in the list) exactly 5 times
4. $ mean end of the string

You can learn and train regex on https://regex101.com/

Answer 3

username=input("input username= ") to_deny = "!? /,.[]()" if any(char in username for char in to_deny): print("denied characters: ?, !, space(s), /, dots, [], ()") quit() elif len(username) != 5: print("username must be at least 5 characters") quit() else: print(f"hello {username}!")