Hi sorry I'm new to Pandas. I was wondering how to input the index of whatever column I am trying to perform the function on. I tried df[column].index
but I keep getting IndexError
on those lines I use it in.
For context I am trying to find the index at which a certain value (-10) is passed for each column which is cd
. Then I have to interpolate it to find the exact value at which -10 occurs which is cd10
.
Thank you so much in advance!
for column in df.columns[1:]:
cd = HERdf.loc[df.iloc[: , df[column].index] <= -10].index[0]
cd10 = np.interp(x = -10 , xp = df.iloc[cd-1:cd+2 , df[column].index] , fp = df.iloc[cd-1:cd+2 , 0] )
print (cd10)
I cannot reproduce your code as I do not fully understand how your dataframe is structured and I did not fully understand the interpolation part but I would try to suggest a solution to your problem purely from your description.
From the description I guess that you want to get the numeric index of a column from column name. Please correct me if I am wrong and the interpolation is a significant part of the question.
You can do it by converting the column index of the dataframe to a list.
for column in df.columns[1:]:
column_index = df.columns.tolist().index(column)
print(f'column index of {column} is {column_index}')
Another option which looks more pythonic to me would be to enumerate the columns:
for column_index, column in enumerate(df.columns[1:], start=1):
print(f'column index of {column} is {column_index}')
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