I want to extract only the numbers before a list of specific words. Then put the extracted numbers in a new column.
The list of words is: l = ["car", "truck", "van"]
. I only put singular form here, but it should also apply to plural.
df = pd.DataFrame(columns=["description"], data=[["have 3 cars"], ["a 1-car situation"], ["may be 2 trucks"]])
We can call the new column for extracted number df["extracted_num"]
Thank you!
You can use Series.str.extract
l = ["car", "truck", "van"]
pat = f"(\d+)[\s-](?:{'|'.join(l)})"
df['extracted_num'] = df['description'].str.extract(pat)
Output:
>>> print(pat)
(\d+)[\s-](?:car|truck|van)
>>> df
description extracted_num
0 have 3 cars 3
1 a 1-car situation 1
2 may be 2 trucks 2
Explanation:
(\d+)
- Matches one or more digits and captures the group; [\s-]
- Matches a single space or hyphen; (?:{'|'.join(l)})"
- Matches any word from the list l
without capturing it.
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