How do I return the element in a list that evaluate to true?

Question

For example, if I wanted to know what numbers are divisible by 2 and had

test_list = [6, 4, 8, 9, 10] print([number % 2 == 0 for number in test_list])

which would evaluate to:

[True, True, True, False, True]

What can I do to get the elements that evaluate to True in a list? Like this:

[6, 4, 8, 10]

(in python)

Answer 1

How about this?

print([x for x in test_list if x % 2 == 0])

Answer 2

Use list comprehension

print([num for num in test_list if num % 2 == 0])

[6, 4, 8, 10]

Answer 3

Ok, you where very close to the solution. In your list comprehension you told the program to put in the list not number , the actual member of your list, but number % 2 == 0 , that is of course a bool type.

To get the list you want, you have to tell the comprehension to get number from test_list each time the condition you want is met (in your case that it's even)

print([number for number in test_list if number % 2 == 0])