How to delete duplicates rows based on 5 columns SQL

Question

loading_tracking_id	loading_id	loading_num	time	event	name	name_en
3830640	111111	105416102020	2021-07-01 01:59:00	office	London	UK
3830641	22222	402055656444	2022-03-02 08:02:13	courier	Paris	FR
3830642	111111	105416102020	2021-07-01 01:59:00	office	London	UK
3830643	111111	105416102020	2021-07-01 01:59:00	office	London	UK
3830644	111111	105416102020	2021-07-01 01:59:00	office	London	UK
3830645	111111	105416102020	2021-07-01 01:59:00	office	London	UK

I have almost no SQL knowledge and need help. I have a database table from which I want to delete duplicates, leaving only one result (no matter the first or the last)

I need to delete all dupications where column "loading_id" has the same data for loading_num, time, event and name. I want to delete all duplications and keep just one of them.

Server version: 10.3.37-MariaDB - MariaDB Server

no skills to be able to test any sql code

Answer 1

DELETE FROM MariaDB  
WHERE loading_tracking_id NOT IN
(
  SELECT MAX(loading_tracking_id) FROM MariaDB 
  GROUP BY loading_id, loading_num, time, event, name, name_en
);