I have a dataframe like this
Value. | Date |
---|---|
A | 08/08/2009 |
A | 09/12/2021 |
A | 05/10/2022 |
A | 06/09/2022 |
A | 07/08/2022 |
I need output like
VALUE | DATE |
---|---|
A | 05/10/2022 |
A | 06/09/2022 |
A | 07/08/2022 |
We have to print a latest year with all month data present in the date column.please refer output table.
i used SQL query like
Select Top 10 * from table where Order by (Date) DESC;
The max() select only one date so that didn't help me
But didn't get expected answer. Can please someone help me with the query?
You can just use MAX
in a subquery, this will produce the intended outcome you have shown in your question:
SELECT yourcolumn
FROM yourtable
WHERE
YEAR(yourcolumn) = (SELECT MAX(YEAR(yourcolumn)) FROM yourtable);
The latest year is 2022, so MAX
in the subquery will find this year and the whole query will select all dates in 2022.
SELECT *
FROM tablename
WHERE datecolumn >= (SELECT DATE_FORMAT(MAX(datecolumn), '%Y-01-01')
FROM tablename)
To improve this query you'd have an index by datecolumn
(or where this column is an expression prefix).
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