How to assign to char from const char *

Question

I have the following C code

int main (int argc, const char *argv[]){

int counter = 1;
char input[1000000];

while(argv[counter] != NULL){
input[counter] = argv[counter]
}

return 0;
}

This gives the warning incompatible pointer to integer conversion assigning to 'char' from 'const char *' [-Wint-conversion]

I can loop through and print out the values of argv[counter] so im confused why i can't set a variable equal to them.

Answer 1

argv is an array of const string while input is an array of character. So your first step is to make input array of string by doing this char *input[1000000] and lastly you have to cast each const string of argv before assigning it to input by doing this input[counter] = (char *)argv[counter] .

Edit Suggested By @David Ranieri

You can remove const from argv to avoid the casting.

ALSO

As @NoDakker said in the comment section. You have to increment counter to avoid infinite loop.

Solution

#include <stdlib.h>

int main (int argc, const char *argv[]){

int counter = 1;
char *input[1000000];

while(argv[counter] != NULL){
input[counter] = (char *)argv[counter];
counter++;
}

return 0;
}