Java regex to remove all trailing numbers?

Question

I want to remove any numbers from the end of a string, for example:

"TestUser12324" -> "TestUser"
"User2Allow555" -> "User2Allow"
"AnotherUser" -> "AnotherUser"
"Test123" -> "Test"

etc.

Anyone know how to do this with a regular expression in Java?

Answer 1

This should work for the Java String class, where myString contains the username:

myString = myString.replaceAll("\\d*$", "");

This should match any number of trailing digit characters (0-9) that come at the end of the string and replace them with an empty string.

.

Answer 2

假设值在字符串中，s：

    s = s.replaceAll("[0-9]*$", "");

Answer 3

这应该是正确的表达方式：

(.+[^0-9])\d*$