Declare 3d array with dynamic 3th dimension in C#

Question

I need to declare 3d array variable but can't.

int[][][]  ary = new int[5][2][];
ary[0,0] = new int[20];
ary[0,1] = new int[3];

Could you please help me!

Thanks in advance Hamid

Answer 1

int[,][] ary = new int[5,2][];

declares a 2D array of int[] objects and initializes it. Use

ary[0, 0] = new int[10];
ary[0, 0][0] = 42;

to access elements.

Note that in C#, multidimensional arrays are different from arrays of arrays. That is, int[][][] is a single dimensional array of single dimensional arrays of single dimensional arrays of integers while int[,,] is a three dimensional array of integers.