Is this an idiomatic way to convert a Guid
to a Guid?
?
new Guid?(new Guid(myString));
No, this is:
Guid? foo = new Guid(myString);
There's an implicit conversion from T
to Nullable<T>
- you don't need to do anything special. Or if you're not in a situation where the implicit conversion will work (eg you're trying to call a method which has overloads for both the nullable and non-nullable types), you can cast it:
(Guid?) new Guid(myString)
just cast it: (Guid?)(new Guid(myString))
there is also an implicit cast, so this would work fine as well: Guid? g = new Guid(myString);
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