This problem has bugged me for years, and I always feel like I'm coming up with a hack when there's a much better solution. The issue at hand occurs when you want to do something to all items in a list and then add something inbetween those items. In short, I want to:
For example, let's say I have a class called Equation
:
public class Equation
{
public string LeftSide { get; set; }
public string Operator { get; set; }
public string RightSide { get; set; }
}
I want to iterate over a list of Equation
s and return a string that formats these items together; something like the following:
public string FormatEquationList(List<Equation> listEquations)
{
string output = string.Empty;
foreach (Equation e in listEquations)
{
//format the Equation
string equation = "(" + e.LeftSide + e.Operator + e.RightSide + ")";
//format the "inbetween" part
string inbetween = " and ";
//concatenate the Equation and "inbetween" part to the output
output += equation + inbetween;
}
return ouput;
}
The problem with the above code is that it is going to include and
at the end of the returned string. I know that I could hack some code together, replace the foreach
with a for
loop, and add the inbetween
element only if it's not the last item; but this seems like a hack.
Is there a standard methodology for how to deal with this type of problem?
You basically have a few different strategies for dealing with this kind problem:
Any of these options can be a legitimate way to implement a "between the items" style of algorithm. Which one you choose depends on things like:
Amongst other things. For the specific case of string, I personally prefer using string.Join()
, as I find it illustrates the intent most clearly. Also, in the case of strings, if you aren't using string.Join()
, you should try to use StringBuilder
to avoid creating too many temporary strings (a consequence of strings being immutable in .Net).
Using string concatentation as the example, the different options break down into examples as follows. (For simplicity, assume Equation has ToString()
as: "(" + LeftSide + Operator + RightSide + ")"
public string FormatEquation( IEnumerable<Equation> listEquations )
{
StringBuilder sb = new StringBuilder();
if( listEquations.Count > 0 )
sb.Append( listEquations[0].ToString() );
for( int i = 1; i < listEquations.Count; i++ )
sb.Append( " and " + listEquations[i].ToString() );
return sb.ToString();
}
The second option looks like:
public string FormatEquation( IEnumerable<Equation> listEquations )
{
StringBuilder sb = new StringBuilder();
const string separator = " and ";
foreach( var eq in listEquations )
sb.Append( eq.ToString() + separator );
if( listEquations.Count > 1 )
sb.Remove( sb.Length, separator.Length );
}
The third would look something like:
public string FormatEquation( IEnumerable<Equation> listEquations )
{
StringBuilder sb = new StringBuilder();
const string separator = " and ";
foreach( var eq in listEquations )
{
sb.Append( eq.ToString() );
if( index == list.Equations.Count-1 )
break;
sb.Append( separator );
}
}
The last option can take multiple forms in .NET, using either String.Join or Linq:
public string FormatEquation( IEnumerable<Equation> listEquations )
{
return string.Join( " and ", listEquations.Select( eq => eq.ToString() ).ToArray() );
}
or:
public string FormatEquation( IEnumerable<Equation> listEquations )
{
return listEquations.Aggregate((a, b) => a.ToString() + " and " + b.ToString() );
}
Personally, I avoid using Aggregate()
for string concatenation because it results in many intermediate, discarded strings. It's also not the most obvious way to "join" a bunch of results together - it's primarily geared for computing a "scalar" results from a collection in some arbitrary, caller-defined fashion.
您可以使用String.Join() 。
String.Join(" and ",listEquations.Select(e=>String.Format("({0}{1}{2})",e.LeftSide,e.Operator,e.RightSide).ToArray());
You can do this with LINQ's Aggregate
operator:
public string FormatEquationList(List<Equation> listEquations)
{
return listEquations.Aggregate((a, b) =>
"(" + a.LeftSide + a.Operator + a.RightSide + ") and (" +
b.LeftSide + b.Operator + b.RightSide + ")");
}
Using a for
loop with counter is perfectly reasonable if you don't want a foreach
loop. This is why there is more than one type of looping statement.
If you want to process items pairwise, loop at LINQ's Aggregate
operator.
I usualy add it before the condition, and check if its the 1st item.
public string FormatEquationList(List<Equation> listEquations)
{
string output = string.Empty;
foreach (Equation e in listEquations)
{
//use conditional to insert your "between" data:
output += (output == String.Empty) ? string.Empty : " and ";
//format the Equation
output += "(" + e.LeftSide + e.Operator + e.RightSide + ")";
}
return ouput;
}
I have to say I would look at the string.Join() function as well, +1 for Linqiness on that. My example is a more of a traditional solution.
I generally try to prefix separators based on a condition rather than add them to the end.
string output = string.Empty;
for (int i = 0; i < 10; i++)
{
output += output == string.Empty ? i.ToString() : " and " + i.ToString();
}
0 and 1 and 2 and 3 and 4 and 5 and 6 and 7 and 8 and 9
I like the String.Join method already posted.
But when you're not using an Array this has normally been my solution to this problem:
public string FormatEquationList(List<Equation> listEquations)
{
string output = string.Empty;
foreach (Equation e in listEquations)
{
// only append " and " when there's something to append to
if (output != string.Empty)
output += " and ";
output += "(" + e.LeftSide + e.Operator + e.RightSide + ")";
}
return output;
}
Of course, it's usually faster to use a StringBuilder:
public string FormatEquationList(List<Equation> listEquations)
{
StringBuilder output = new StringBuilder();
foreach (Equation e in listEquations)
{
// only append " and " when there's something to append to
if (output.Length > 0)
output.Append(" and ");
output.Append("(");
output.Append(e.LeftSide);
output.Append(e.Operator);
output.Append(e.RightSide);
output.Append(")");
}
return output.ToString();
}
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