Last matching symbol in Regex

Question

I couldn't find a more descriptive title, but here there is an example:

import re
m = re.search(r"\((?P<remixer>.+) (Remix)\)", "Title (Menda Remix)")
m.group("remixer") # returns 'Menda' OK
m = re.search(r"\((?P<remixer>.+) (Remix)\)", "Title (Blabla) (Menda Remix)")
m.group("remixer") # returns 'Blabla) (Menda' FAIL

This regex finds the first parenthesis, and I would like to match the last parenthesis for always getting 'Menda'. I've made a workaround to this using extra functions, but I would like a cleaner and a more consistent way using the same regex.

Thanks a lot guys.

Answer 1

re.search(r"\((?P<remixer>[^)]+) (Remix)\)", "Title (Blabla) (Menda Remix)")

Answer 2

使用[^()]+而不是.+来不匹配括号。

Answer 3

我可能会这样做：

m = re.search(r".*\((?P<remixer>.+) (Remix)\)", "Title (Blabla) (Menda Remix)")

Answer 4

Just add a $ to the end of the pattern and you're done :)

import re
m = re.search(r"\((?P<remixer>[^)]+) (Remix)\)$", "Title (Menda Remix)")
print m.group("remixer") # returns 'Menda' OK
m = re.search(r"\((?P<remixer>[^)]+) (Remix)\)$", "Title (Blabla) (Menda Remix)")
print m.group("remixer") # returns 'Blabla) (Menda' FAIL

PS: I've also changed the .+ to [^)]+ so you won't match any ) in the process.