Python - multi-line array

Question

in c++ I can wrote:

int someArray[8][8];
for (int i=0; i < 7; i++)
   for (int j=0; j < 7; j++)
      someArray[i][j] = 0;

And how can I initialize multi-line arrays in python? I tried:

array = [[],[]]
for i in xrange(8):
   for j in xrange(8):
        array[i][j] = 0

Answer 1

>>> [[0]*8 for x in xrange(8)]
[[0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0]]
>>>

Answer 2

You asked about initializing a list of lists. Its a very useful data structure, but it has an important difference from the 2D array in C++: There are no guarantees that all lines have the same length (ie, that len(a[0])==len(a[1]) (while in C++ you do have that guarantee).

So another solution that might be handy, is using NumPy 's array datatype, like this:

import numpy as np
array = np.zeros((8,8))

Answer 3

Here is a shorter way:

array = []
for i in xrange(8):
    array.append( [0] * 8 )

Answer 4

array = [[0]*8 for i in xrange(8)]

Answer 5

[[0]*8 for x in range(8)]