What is the C equivalent of C++
delete[] (char *) foo->bar;
Edit: I'm converting some C++ code to ANSI C. And it had:
typedef struct keyvalue
{
char *key;
void *value;
struct keyvalue *next;
} keyvalue_rec;
// ...
for (
ptr = this->_properties->next, last = this->_properties;
ptr!=NULL;
last = ptr, ptr = ptr->next)
{
delete[] last->key;
delete[] (char *) last->value;
delete last;
}
Would this do it for C ?
free(last->key);
free(last->value);
free(last)
In C, you don't have new
; you just have malloc()
; to free memory obtained by a call to malloc()
, free()
is called.
That said, why would you cast a pointer to (char*)
before passing it to delete
? That's almost certainly wrong: the pointer passed to delete
must be of the same type as created with new
(or, if it has class type, then of a base class with a virtual destructor).
Just plain 'ol free()
. C makes no distinction between arrays and individual variables.
相当于delete
和delete[]
的C语言是free
吗?
与非数组相同。
free(foo->bar)
The equivalent would be:
free(foo->bar);
since you were typecasting it to (char *) which means whatever the actual type of 'bar' was there would have been no destructor called as a result of the cast.
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