Java regular expression needed to separate phone number and text in brackets

Question

I'd like a regular expression for Java that can take this string

+1 7183541169 (East coast)

And produce two groups

• +1 7183541169
• East coast

I'm having difficulty with escaping the round brackets.

Answer 1

Should be:

^(.*)\((.*)\)$

This assumes no special format - it will accept digits or letters anywhere. The regex reads:

^ - Start of the string
(.*) - some letters (captured group)
\\( - literal (
(.*) - more letters (captured group)
\\) - literal )
$ - end of string

Keep in mind it is a relatively easy task, and you can solve it with simple string manipulation.

Answer 2

/^(\+\d{1} \d+) \(((?:\w| |-)+)\)$/i

我不知道你的字符串的规则，但这应该工作。