简体   繁体   中英

Sorting ArrayList of Objects by Object attribute

I am having an Arraylist of Objects. Those object have an attribute or datatype - 'String'. I need to sort the Arraylist by that string. How to achieve this?

You need to write a Comparator<MyObject> and use Collections.sort(List<T>, Comparator<? super T> to sort your List .

Or else, your MyObject can also implements Comparable<MyObject> , defining a natural ordering that compares on your specific attribute, and then use Collections.sort(List<T> instead.

See also

Related questions

On sorting List on various criteria:

On Comparator and Comparable

Another good way of doing this that is a bit more flexible if there is more than one property of an object that you may wish to sort by is to use Guava 's Ordering class with its onResultOf(Function) option. This is ideally suited for sorting by properties since a Function can be used to retrieve and return a specific property of an object. For a simple example, imagine a class Person with String getFirstName() and String getLastName() methods.

List<Person> people = ...;
Collections.sort(people, Ordering.natural().onResultOf(
    new Function<Person, String>() {
      public String apply(Person from) {
        return from.getFirstName();
      }
    }));

The above will sort the list by first name.

To make it read nicer, you may want to define the functions you might want to use as public static final fields on the Person class. Then you could sort by last name like this:

Collections.sort(people, Ordering.natural().onResultOf(Person.GET_LAST_NAME));

As a fun aside note, this will all be a lot easier in Java 8 with lambda expressions and method references. You'll be able to write something like this without having to define any clumsy anonymous inner classes or static final fields:

import static java.util.Comparator.comparing;
...

people.sort(comparing(Person::getLastName));

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM