I want to validate URL (using java script) to accept only format - http://www.test.com . I'm trying following code, but it accepts test.com and http://www.test.com.com also.
var URLReg = new RegExp();
URLReg.compile("^[A-Za-z]+://[A-Za-z0-9-_]+\\.[A-Za-z0-9-_%&\?\/.=]+$");
if (!URLReg.test(form["URL"].value)) {
alert("You must supply a valid URL.");
return false;
}
what is wrong in this ? :(
Thanks in advance.
If you want to stick partially to your code a quick fix could simply use these:
"^((https?\\\\://www\\\\.)|(www\\\\.))[A-Za-z0-9_\\\\-]+\\\\.[A-Za-z0-9_\\\\-\\\\%\\\\&\\\\?\\\\.\\\\=\\\\+]+$"
(accepts " http://www ...." and "www...")
or
"^(https?\\\\://www\\\\.)[A-Za-z0-9_\\\\-]+\\\\.[A-Za-z0-9_\\\\-\\\\%\\\\&\\\\?\\\\.\\\\=\\\\+]+$"
(accepts only " http://www ...." and NOT "www...")
Neither ones of the above accepts a domain without "www".
Anyway your code (and also the adjusted code I placed above) is WRONG because they would both validate ok domains like these:
Your regex would also accept a crap like this:
To validate just the domain part ( forcing www to be entered ) you can use this:
var URLReg = /^((https?\://wwww\.)|(www\.))([a-z0-9]([a-z0-9]|(\-[a-z0-9]))*\.)+[a-z]+$/i;
This one won't validate ok crap like:
BTW: It would validate also http://www.domain.com.com but this is not an error because a subdomain url could be like: http://www.subdomain.domain.com and it's valid! And there is almost no way (or at least no operatively easy way) to validate for proper domain tld with a regex because you would have to write inline into your regex all possible domain tlds ONE BY ONE like this:
var URLReg = /^((https?\://wwww\.)|(www\.))([a-z0-9]([a-z0-9]|(\-[a-z0-9]))*\.)+(com|it|net|uk|de)$/i;
(this last one for instance would validate only domain ending with .com/.net/.de/.it/.co.uk) New tlds always come out , so you would have to adjust you regex everytimne a new tld comes out, that's odd!
In order to validate also the remaining part of an url you could add the remainig part at the end of the regex:
var URLReg = /^((https?\\://wwww\\.)|(www\\.))([a-z0-9]([a-z0-9]|(\\-[a-z0-9]))*\\.)+[az]+(\\/[a-z0-9_\\-\\%\\&\\?\\.\\=\\+]*)*$/i
;
It's still not perfect because somone could enter:
http://www.domain.com/????hello
and it would validate ok, but now I'm tired, sorry! :)
i use this expression - its the best i found:
^(https?://)?(([\w!~*'().&=+$%-]+: )?[\w!~*'().&=+$%-]+@)?(([0-9]{1,3}\.){3}[0-9]{1,3}|([\w!~*'()-]+\.)*
([\w^-][\w-]{0,61})?[\w]\.[a-z]{2,6})(:[0-9]{1,4})?((/*)|(/+[\w!~*'().;?:
@&=+$,%#-]+)+/*)$
See if
^[A-Za-z]+:\/\/[A-Za-z0-9-/]+\.com$
is what you want
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