If data is in the following format:
SID TID Tdatetime QID QTotal
----------------------------------------
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 9:00AM 66 110
100 1 01/12/97 10:00AM 67 110
100 2 01/19/97 9:00AM 66 .
100 2 01/19/97 9:00AM 66 110
100 2 01/19/97 10:00AM 66 110
100 3 01/26/97 9:00AM 68 120
100 3 01/26/97 9:00AM 68 120
110 1 02/03/97 10:00AM 68 110
110 3 02/12/97 9:00AM 64 115
110 3 02/12/97 9:00AM 64 115
120 1 04/05/97 9:00AM 66 105
120 1 04/05/97 10:00AM 66 105
I would like to be able to write a query to sum the QTotal column for all rows and find the count of duplicate rows for the Tdatetime column.
The output would look like:
Year Total Count
97 | 1340 | 4
The third column in the result does not include the count of distinct rows in the table.
And the output is grouped by the year in the TDateTime column.
This will work if you really want to group by the tDateTime column:
SELECT DISTINCT tDateTime, SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY tDateTime
HAVING Count(distinct tDateTime) > 1
But your results look like you want to group by the Year in the tDateTime column. Is this correct?
If so try this:
SELECT DISTINCT YEAR (tDateTime), SUM(QTotal), Count(distinct tDateTime)
FROM Table
GROUP BY YEAR (tDateTime)
HAVING Count(distinct tDateTime) > 1
The following query may help:
SELECT
'YEAR ' + CAST(sub.theYear AS VARCHAR(4)),
COUNT(sub.C),
(SELECT SUM(QTotal) FROM MyTable WHERE YEAR(Tdatetime) = sub.theYear) AS total
FROM
(SELECT
YEAR(Tdatetime) AS theYear,
COUNT(Tdatetime) AS C
FROM MyTable
GROUP BY Tdatetime, YEAR(Tdatetime)
HAVING COUNT(Tdatetime) >= 2) AS sub
You must do SELECT from this table GROUPing by QTotal, using COUNT(subSELECT from this table WHERE QTotal is the same). If I only I had time I would write you SQL statement, but it'll take some minutes.
Something like:
select Year(Tdatetime) ,sum(QTotal), count(1) from table group by year(Tdatetime )
or full date
select Tdatetime ,sum(QTotal), count(1) from table group by year(Tdatetime)
Or your ugly syntax ( : ) )
select 'Year ' + cast(Year(tdatetime) as varchar(4))
+ '|' + cast(sum(QTotal) as varchar(31))
+ '|' + cast(count(1) as varchar(31))
from table group by year(Tdatetime )
Or do you want just the year? Sum all columns? Or just by year?
SELECT
YEar + year(Tdatetime),
SUM ( QTotal ),
(SELECT COUNT(*) FROM (
SELECT Tdatetime FROM tDateTime GROUP BY Tdatetime
HAVING COUNT(QID) > 1) C
FROM
Tdatetime t
GROUP BY
YEar + year(Tdatetime)
This is the first time I have asked a question on stackoverflow. It looks like I have lost my original ID info. I had to register to login and add comments to the question I posted.
To answer OMG Ponies question, this is a SQL Server 2008 database. @Abe Miessler , the row with SID 120 does not contain duplicates. the first row for SID 120 shows 9:00AM in the datetime column , and the second row shows 10:00AM.
@Zafer, your query is the accepted answer. I made a few minor tweaks to get it to work. Thanks. Thanks due to Abe Miessler and the others for your help.
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