regular expression for string that starts with 'http://'

Question

大家好，就像标题中一样-我需要使用匹配以'http：//'开头的任何内容的正则表达式

Answer 1

Is that really what you want?

This will match everything up to the first whitespace: ^http://[^\\s]*

Answer 2

Why not just look to see if the first 7 characters are "http://"

substr($url, 0, 7) == "http://"

No need for regexps here.

Answer 3

这应该做到这一点： ^http://.*

Answer 4

所以从根本上讲，您想匹配字符串中的URL吗？

http://([-\w\.]+)+(:\d+)?(/([\w/_\.]*(\?\S+)?)?)?