$ptn = "/^Response.+?[:] /";
$str = "Response from Moore Auto: Thanks for your feedback";
$rpltxt = "";
echo preg_replace($ptn, $rpltxt, $str);
"Moore Auto" is a variable name, so I simply need the text after the colon and space. Desired final result would be the string "Thanks for your feedback" in this case. Much appreciated!
Simple with substr()
, like this:
$str = 'Response from Moore Auto: Thanks for your feedback';
echo substr($str, strpos($str,':')+2); //echoes "Thanks for your feedback"
Damiens solution does not work, if there is more than one colon. This should always work if the first part doesn't contain a colon:
<?php
$ptn = "/^Response[^:]+:\s*(.*)$/";
$str = "Response from Moore Auto: Thanks for your feedback";
if (preg_match($ptn, $str, $match)) {
$text = $match[1];
echo $text; //Thanks for your feedback
}
?>
try
<?php
$ptn = "/^(Response.+[:])(.*?)/";
$str = "Response from Moore Auto: Thanks for your feedback";
$rpltxt = "$2";
echo preg_replace($ptn, $rpltxt, $str);
?>
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