Need to match any string ends up with a letter, and the second last character is '>'
It will match:
abc>a
ddd_4>f
It will not match:
abc>ab
abc>2
>>> import re
>>> s = 'abc>a'
>>> r = re.compile(r'>[:alpha:]$')
>>> print( r.search(s) )
<_sre.SRE_Match object at 0xb76c5a30>
>>>
If you want to match letters according to locales.
re.compile(r'.*>[a-zA-Z]$')
should generate the pattern that you want.
However, I recommend that you take a read through the regexp part of Google's Python class . Then you can learn how to do things like this yourself.
.*>[a-zA-Z]$
>>> for s in ('abc>a', 'ddd_4>f', 'abc>ab', 'abc>2'):
... print re.match(r'.*>[a-zA-Z]$', s)
...
<_sre.SRE_Match object at 0xb7217e58>
<_sre.SRE_Match object at 0xb7217e58>
None
None
I think this is what you are looking for:
import re
re.search(">[a-zA-Z]$", str)
It will evaluate to None
if the string does not match.
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