I am very new to both Python and regular expressions, so bear with me. I have some text that looks like this:
Change 421387 on 2011/09/20 by person@domain.com Some random text including line breaks Change 421388 on 2011/09/20 by person2@domain.com Some other random text including line breaks
Now, I want to use python along with a regular expression to split this into a tuple. In the end I want the tuple to contain two elements.
Element 0:
Change 421387 on 2011/09/20 by person@domain.com Some random text including line breaks
Element 1:
Change 421388 on 2011/09/20 by person2@domain.com Some other random text including line breaks
I realize that I can use regex to recognize the pattern formed by:
@
I know it could be broken down further, but I think recognizing these things is good enough for my purposes.
Once I come up with a regular expression for that pattern, how can I use it to split the string into a tuple of strings?
With a lookahead assertion.
>>> re.split(r'(?=\s+Change \d+ on \d{4})\s+', ''' Change 421387 on 2011/09/20 by person@domain.com
... Some random text including line breaks
... Change 421388 on 2011/09/20 by person2@domain.com
... Some other random text including line breaks''')
['', 'Change 421387 on 2011/09/20 by person@domain.com\n Some random text including line breaks', 'Change 421388 on 2011/09/20 by person2@domain.com\n Some other random text including line breaks']
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