I've been wondering about the following issue: assume I have a C style function that reads raw data into a buffer
int recv_n(int handle, void* buf, size_t len);
Can I read the data directly into an std:string
or stringstream
without allocating any temporal buffers? For example,
std::string s(100, '\0');
recv_n(handle, s.data(), 100);
I guess this solution has an undefined outcome, because, afaik, string::c_str
and string::data
might return a temporal location and not necessarily return the pointer to the real place in the memory, used by the object to store the data.
Any ideas?
Why not use a vector<char>
instead of a string
? That way you can do:
vector<char> v(100, '\0');
recv_n(handle, &v[0], 100);
This seems more idiomatic to me, especially since you aren't using it as a string (you say it's raw data).
Yes, after C++11.
But you cant use s.data()
as it returns a char const*
Try:
std::string s(100, '\0');
recv_n(handle, &s[0], 100);
Depending on situation, I may have chosen a std::vector<char> especially for raw data (though it would all depend on usage of the data in your application).
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