PHP execute command as subcommand

Question

I have the following 2 files and am executing them on linux (debian).

File1.php

<?php
exec("php -f file2.php > /dev/null 2>&1 &");
sleep(100);

File2.php

<?php
exec("sleep 30 > /dev/null 2>&1 &");
exec("sleep 30 > /dev/null 2>&1 &");
sleep(100);

The way it currently is it first starts file1.php and fires up file2.php and immediatly begins the sleep commands. It does not wait for the first sleep to finish to continue.

The problem is that the file2.php and sleep commands are not subcommands of file1.php and I can't simply kill it to kill all subcommands. My htop looks like this: http://dl.getdropbox.com/u/5910/Jing/2011-01-13_1611.png

I am searching for a way to have the commands be subcommands of file1.php so that I can easily kill them all :)

what I have:

'- php -f file2.php
'-sleep 30
'-sleep 30
'- php -f file1.php

basically I want this:

'- php -f file1.php
  '- php -f file2.php
    '-sleep 30
    '-sleep 30

Answer 1

I haven't looked into it too much, but my first guess would be to fork it from file1.

http://php.net/manual/en/function.pcntl-fork.php

I can take a better look later, but you should be able to use pcntl_waitpid($pid) for the fork to complete.

Answer 2

popen and proc_open seem to do it :)

file1.php

<?php
$descs = array(
   0 => array("pipe", "r"),
   1 => array("pipe", "w"),
   2 => array("file", "/tmp/error-output.txt", "a")
);
$process = proc_open("php -f file2.php", $descs, $pipess);
sleep(100);

file2.php

<?php
$desc = array(
   0 => array("pipe", "r"),
   1 => array("pipe", "w"),
   2 => array("file", "/tmp/error-output.txt", "a")
);
echo "asd";
$process[] = proc_open("sleep 12", $desc, $pipes);
echo "sleep!";
$process[] = proc_open("sleep 10", $desc, $pipes);
echo "asd";

Answer 3

include('file2.php');

它应该立即执行命令