How to compile multiple java source files in command line

Question

I know running javac file1.java produces file1.class if file1.java is the only source file, then I can just say java file1 to run it.

However, if I have 2 source files, file1.java and file2.java , then how do I build the program?

Answer 1

请尝试以下方法：

javac file1.java file2.java

Answer 2

或者您可以使用以下命令编译当前目录中的所有Java源文件。

javac *.java

Answer 3

Here is another example, for compiling a java file in a nested directory.

I was trying to build this from the command line. This is an example from 'gradle', which has dependency 'commons-collection.jar'. For more info, please see ' gradle: java quickstart ' example. -- of course, you would use the 'gradle' tools to build it. But i thought to extend this example, for a nested java project, with a dependent jar.

Note: You need the 'gradle binary or source' distribution for this, example code is in: 'samples/java/quickstart'

% mkdir -p temp/classes
% curl --get \
    http://central.maven.org/maven2/commons-collections/commons-collections/3.2.2/commons-collections-3.2.2.jar \
        --output commons-collections-3.2.2.jar

% javac -g -classpath commons-collections-3.2.2.jar \
     -sourcepath src/main/java -d temp/classes \
      src/main/java/org/gradle/Person.java 

% jar cf my_example.jar -C temp/classes org/gradle/Person.class
% jar tvf my_example.jar
   0 Wed Jun 07 14:11:56 CEST 2017 META-INF/
  69 Wed Jun 07 14:11:56 CEST 2017 META-INF/MANIFEST.MF
 519 Wed Jun 07 13:58:06 CEST 2017 org/gradle/Person.class

Answer 4

1. use wildcard

2. use options

3. https://docs.oracle.com/javase/8/docs/technotes/tools/windows/javac.html

Answer 5

或者您可以使用javac file1.java然后使用javac file2.java 。