When I execute the following code
return entityManager
.createQuery("select a from Article where a.slug = ?1", Article.class)
.setParameter(1, slug)
.getSingleResult();
I get the following exception
java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager:
Exception Description: Syntax error parsing the query [select a from Article where a.slug = '?1'], line 1, column 22: syntax error at [where].
Internal Exception: MismatchedTokenException(77!=78)
at org.eclipse.persistence.internal.jpa.EntityManagerImpl.createQuery(EntityManagerImpl.java:1328)
I'm using JPA 2 with EclipseLink 2.0.2.
What is wrong with my query?
......来自文章a ...(遗漏别名)
Well, the answer has alredy given.. But what I dont like about JPQL, you have to put an identifier after Entity name, but it is uncessary if your from clause does have only one Entity. Most of time, I also forget to put that unnecessarily required identifier. I wish I would write the above query as below;
select * from Article where slug = ?1
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