Using Python, get the day of the current month as an integer

Question

I need to write a method that returns the day of the month as an integer. For example, if it's Feb 8th 2011, I want to have method like this:

>>> day = get_day_of_month()

where day would be given the integer value 8

Answer 1

>>> import datetime
>>> datetime.datetime.today().day

Answer 2

from datetime import datetime

today = datetime.now()
today.day # this is a integer

Answer 3

Or the "old school" (lower overhead, if it matters) method...

import time 
time.localtime(time.time())[2]

time.localtime() returns a tuple containing all of the elements of a timestamp.

Answer 4

This is similar to the answer by programmersbook . It uses datetime.date rather than datetime.datetime .

>>> import datetime
>>> datetime.date.today().day
8