I was wondering if it is possible to enter in binary numbers and have them translated back into text. For example I would enter "01101000 01100101 01101100 01101100 01101111" and it would covert it into the word "hello".
Just some logical corrections:
There are three steps here
Luckily parseInt
takes a radix
argument for the base. So, once you either chop the string up into (presumably) an array of strings of length 8, or access the necessary substring, all you need to do is (char)Integer.parseInt(s, 2)
and concatenate.
String s2 = "";
char nextChar;
for(int i = 0; i <= s.length()-8; i += 9) //this is a little tricky. we want [0, 7], [9, 16], etc (increment index by 9 if bytes are space-delimited)
{
nextChar = (char)Integer.parseInt(s.substring(i, i+8), 2);
s2 += nextChar;
}
请参阅此问题的答案: binary-to-text-in-java 。
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