problem in query order by decending

Question

i have 29 rows in mytable with datetime(dt). I want to sort it in descending order when i query the table it give the result starting from 28 (29 not given) and after 28 it starts from 1, 2....27 where (1-27 datetime is 0000-00-00 00:00:00) and 29 has the recent time.

$dt1=$_GET['dt'];
$query="SELECT * FROM table ORDER BY dt DESC";
$result1 = mysql_query($query);
$table = mysql_fetch_array($result1, MYSQL_ASSOC);
$dt2=$table['dt'];
echo $dt2."
";   // if here i echo $table['id'];  the result is here 29 
if(strtotime($dt1) <  strtotime($dt2))
{
while ($table = mysql_fetch_array($result1, MYSQL_ASSOC)){

    echo $table['id']."<br />";
    echo $table['name']."<br />";

   }
     }
   else
       echo "false";

Why the last id is not shown ie 29

Answer 1

You read your first line into $table on line 3

$result1 = mysql_query($query);

So when entering your while loop you read the second row into $table causing you to miss the first row.

EDIT : You can prevent this by resetting the rowpointer right before you start your while loop like this:

mysql_data_seek($query,0);
while(..........

Answer 2

you're doing fetch array out of while loop so in while loop you get -1 records from fetch_array.

As I am guessing you're doing the filter by date with GET['dt'] variable.

you can filter records directly in SQL query.

Like this

SELECT * FROM table WHERE dt > {$_GET['dt']} ORDER BY dt DESC

beware to pass the correct format of the date.

Answer 3

Just delete your line $table = mysql_fetch_array($result1, MYSQL_ASSOC); and it will work :

$dt1=$_GET['dt'];
$query="SELECT * FROM table ORDER BY dt DESC";
$result1 = mysql_query($query);
$dt2=$table['dt'];
echo $dt2."
";   // if here i echo $table['id'];  the result is here 29 
if(strtotime($dt1) <  strtotime($dt2))
{
while ($table = mysql_fetch_array($result1, MYSQL_ASSOC)){

    echo $table['id']."<br />";
    echo $table['name']."<br />";

   }
     }
   else
       echo "false";