简体   繁体   中英

updating a input field based on selectlist option

I have the following HTML

<select name="title" id="title">
  <option value="Mrs" >Mrs</option>
  <option value="Mr" >Mr</option>
  <option value="Miss" >Miss</option>
  <option value="Dr" >Dr</option>
</select>

<input type="text" name="gtitle" id="gift_title" value="" />

Now by default Mrs is shown as the first option of the select list. What I need to do then, is to get this value and display it in the input field. Subsequent selections by the user, ie he/she choses Mr , must also update this input field as well.

I was hoping I could this in jQuery, but I wasn't sure how to get these values.

Thanks

You could subscribe for the .change() event of the dropdownlist and update the value of the input:

$(function() {
    // initialize the value of the input field to the selected value
    // of the dropdown list:
    $('#gift_title').val($('#title').val());

    $('#title').change(function() {
        // when the value of the dropdown list changes
        // update the input field
        $('#gift_title').val($(this).val());
    });
});

And here's a live demo .

<select name="title" id="title">
  <option value="Mrs" >Mrs</option>
  <option value="Mr" >Mr</option>
  <option value="Miss" >Miss</option>
  <option value="Dr" >Dr</option>
</select>

<input type="text" name="gtitle" id="gift_title" value="Mrs" />

I added default value to html

$('#title').change(function(){
    $('#gift_title').val(this.value);
});

working demo

but I fail to see any reason for this just use the select value when you submit there should be no need for input feild

In addition to the awnsers provided already, I suggest the following, to populate the input field with the default value of the checkbox at load. Insert something like this between line 4 and 5 of Darin's code:

$('#gift_title').val($('#title').val());

or consider making the change callback function explicit so it could be reused.

Hope this helps!

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM