Hi I am trying to compare two strings in a directory. the format is as follows.
{sametext}difference{sametext}
.
Note: {sametext} is not static for each file
for example
myfile_1_exercise.txt
compared to myfile_2_exercise.txt
Can you tell me how I would match the above strings in an if statement.
Basically I need to know how I would ignore the number in the two strings so that these would be same.
Some example code is shown below:
My example code looks like this:
for g in `ls -d */`;
do
if [ -d $g ]; then
cd $g # down 1 directories
for h in `ls *root`;
do
printf "${Process[${count}]} = ${basedir}/${f}${g}${h}\n"
h1=${h}
if [ "${h1}" = "${h2}" ]; then # NEED to MATCH SOME HOW??????????
echo we have a match
fi
h2=${h1}
let count+=1
done
cd ../
#printf "\n\n\n\n"
fi
done
What should be the test to determine this instead of "${h1}" = "${h2}"
?
Cheers,
Mike
sed
comes in handy here.
This basically goes through every file in the directory, extracts the two strings from the filename, and keeps a list of all the unique combinations thereof.
Then, it walks through this list, and uses bash's wildcard expansion to allow you to loop over each collection.
EDIT: Got rid of an ugly hack.
i=0
for f in *_*_*.txt
do
a=`echo "$f" | sed 's/\(.*\)_.*_\(.*\).txt/\1/g'`
b=`echo "$f" | sed 's/\(.*\)_.*_\(.*\).txt/\2/g'`
tmp=${all[@]}
expr match "$tmp" ".*$a:$b.*" >/dev/null
if [ "$?" == "1" ]
then
all[i]="$a:$b"
let i+=1
fi
done
for f in ${all[@]}
do
a=`echo "$f" | sed 's/\(.*\):\(.*\)/\1/g'`
b=`echo "$f" | sed 's/\(.*\):\(.*\)/\2/g'`
echo $a - $b
for f2 in $a_*_$b.txt
do
echo " $f2"
# ...
done
done
Of course, this assumes that all the files you care about follow the *_*_*.txt
pattern.
"myfile_1_exercise.txt" == "myfile_2_exercise.txt"
You mean the above test should return true
(ignoring the numbers) right?
This is what I would have done:
h1="myfile_1_exercise.txt"
h2="myfile_2_exercise.txt"
if [ $( echo ${h1} | sed 's/[0-9]*//g' ) == $( echo ${h2} | sed 's/[0-9]*//g' ) ] ; then
# do something here.
fi
Disclaimer:
Said that, here is a script that compares two strings according to your requirements. I am sure you can figure how to use it in your directory listing script (for which you may want to consider find
by the way)
This script takes two strings and prints match! if they match
$ bash compare.sh myfile_1_exercise.txt myfile_2_exercise.txt
match!
$ bash compare.sh myfile_1_exercise.txt otherfile_2_exercise.txt
$
The script:
#!/bin/bash
fname1=$1
fname2=$2
findStartMatch() {
match=""
rest1=$1 ;
rest2=$2 ;
char1=""
char2=""
while [[ "$rest1" != "" && "$rest2" != "" && "$char1" == "$char2" ]] ; do
char1=$(echo $rest1 | sed 's/\(.\).*/\1/');
rest1=$(echo $rest1 | sed 's/.\(.*\)/\1/') ;
char2=$(echo $rest2 | sed 's/\(.\).*/\1/');
rest2=$(echo $rest2 | sed 's/.\(.*\)/\1/') ;
if [[ "$char1" == "$char2" ]] ; then
match="${match}${char1}"
fi
done
}
findEndMatch() {
match=""
rest1=$1 ;
rest2=$2 ;
char1=""
char2=""
while [[ "$rest1" != "" && "$rest2" != "" && "$char1" == "$char2" ]] ; do
char1=$(echo $rest1 | sed 's/.*\(.\)/\1/');
rest1=$(echo $rest1 | sed 's/\(.*\)./\1/') ;
char2=$(echo $rest2 | sed 's/.*\(.\)/\1/');
rest2=$(echo $rest2 | sed 's/\(.*\)./\1/') ;
if [[ "$char1" == "$char2" ]] ; then
match="${char1}${match}"
fi
done
}
findStartMatch $fname1 $fname2
startMatch=$match
findEndMatch $fname1 $fname2
endMatch=$match
if [[ "$startMatch" != "" && "$endMatch" != "" ]] ; then
echo "match!"
fi
If you are actually comparing two files like you mentiond... probably you can use diff
command like
diff myfile_1_exercise.txt myfile_2_exercise.txt
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