Alright, Regex gurus, how can I change my logic to fix this one?
I've made a regex:
(,[,]+)
It's supposed to remove extra commas on the end of a line. (end of line being \\r\\n) when formatted as a string.
It works (sort of).
This is the string:
Date,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24,\r\nDate,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24,,,,,\r\nDate,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24,,,,,\r\nDate,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24,,\r\n
When I run that regex, it gives a result of:
Date,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24,\r\nDate,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24\r\nDate,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24\r\nDate,1-Jul-18,1-Jul-19,1-Jul-20,1-Jul-21,1-Jul-22,1-Jul-23,1-Jul-24\r\n
I need to remove the comma at the end of the first line (I think I need to be finding \\r\\n and killing any commas before that, until a non-comma.
Any thoughts about how to do this?
Thanks
(,+$)
perhaps? (One or more commas followed immediately by the end of a line.)
如果您的语言支持正向前进,请尝试以下操作-
([,]*)(?=\\r\\n)
I think you can match one or more ,
followed by \\r\\n
by using ,+\\\\r\\\\n
. Don't know how to replace that using C# sorry. In perl I would do
perl -pi -e 's/,+\\r\\n/\\r\\n/g' c.txt
(assuming that c.txt
is a file containing your input text).
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