A regex to match strings with alphanumeric, spaces and punctuation

Question

我需要一个正则表达式来匹配包含字母，数字，空格和一些简单标点符号的字符串（ .,!"'/$ ）。我有^[A-Za-z0-9 _]*[A-Za-z0-9][A-Za-z0-9 _]*$它适用于字母数字和空格，但不适用于标点符号。非常感谢帮助。

Answer 1

Just add punctuation and other characters inside classes (inside the square brackets):

[A-Za-z0-9 _.,!"'/$]*

This matches every string containing spaces, _, alphanumerics, commas, !, ", $, ... Pay attention while adding some special characters, maybe you need to escape them: more info here

Answer 2

Assuming from your regex that at least one alphanumeric character must be present in the string, then I'd suggest the following:

/^(?=.*[A-Z0-9])[\w.,!"'\/$ ]+$/i

The (?=.*[A-Z0-9]) lookahead checks for the presence of one ASCII letter or digit; the nest character class contains all ASCII alphanumerics including underscore ( \\w ) and the rest of the punctuation characters you mentioned. The slash needs to be escaped because it's also used as a regex delimiter. The /i modifier makes the regex case-insensitive.

Answer 3

<script type="text/javascript">
check("hello dfdf asdjfnbusaobfdoad fsdihfishadio fhsdhf iohdhf");
function check(data){
var patren=/^[A-Za-z0-9\s]+$/;
    if(!(patren.test(data))) {
       alert('Input is not alphanumeric');       
       return false;
    }
    alert(data + " is good");
}
</script>