I want to get rid of all invalid characters; example hexadecimal value 0x1A
from an XML file using sed.
What is the regex and the command line?
EDIT
Added Perl tag hoping to get more responses. I prefer a one-liner solution.
EDIT
These are the valid XML characters
x9 | xA | xD | [x20-xD7FF] | [xE000-xFFFD] | [x10000-x10FFFF]
Assuming UTF-8 XML documents:
perl -CSDA -pe'
s/[^\x9\xA\xD\x20-\x{D7FF}\x{E000}-\x{FFFD}\x{10000}-\x{10FFFF}]+//g;
' file.xml > file_fixed.xml
If you want to encode the bad bytes instead,
perl -CSDA -pe'
s/([^\x9\xA\xD\x20-\x{D7FF}\x{E000}-\x{FFFD}\x{10000}-\x{10FFFF}])/
"&#".ord($1).";"
/xeg;
' file.xml > file_fixed.xml
You can call it a few different ways:
perl -CSDA -pe'...' file.xml > file_fixed.xml
perl -CSDA -i~ -pe'...' file.xml # Inplace with backup
perl -CSDA -i -pe'...' file.xml # Inplace without backup
The tr
command would be simpler. So, try something like:
cat <filename> | tr -d '\032' > <newfilename>
Note that ascii character '0x1a' has the octal value '032', so we use that instead with tr
. Not sure if tr
likes hex.
There is actually a way to do this with sed, like so:
cat input_file | LANG=C sed -E \
-e 's/.*/& /g' \
-e 's/(('\
'[\x9\xa\xd\x20-\x7f]|'\
'[\xc0-\xdf][\x80-\xbf]|'\
'[\xe0-\xec][\x80-\xbf][\x80-\xbf]|'\
'[\xed][\x80-\x9f][\x80-\xbf]|'\
'[\xee-\xef][\x80-\xbf][\x80-\xbf]|'\
'[\xf0][\x80-\x8f][\x80-\xbf][\x80-\xbf]'\
')*)./\1?/g' \
-e 's/(.*)\?/\1/g' \
-e 's|]]>|]]>]]<![CDATA[>|g' > output_file
This works in four steps:
The LANG=C env variable is set to prevent sed from doing charset conversion itself - it should treat every character as 8-bit ascii.
尝试:
perl -pi -e 's/[^\x9\xA\xD\x20-\x{d7ff}\x{e000}-\x{fffd}\x{10000}-\x{10ffff}]//g' file.xml
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