Java String new line
Question
I have a string like
"I am a boy".
I would like to print it this way
"I
am
a
boy".
Can anybody help me?
17 answers
solution1
146 2011-10-20 09:21:08
System.out.println("I\nam\na\nboy");
System.out.println("I am a boy".replaceAll("\\s+","\n"));
System.out.println("I am a boy".replaceAll("\\s+",System.getProperty("line.separator"))); // portable way
solution2
129 2015-07-23 23:46:29
您还可以使用System.lineSeparator() ：
String x = "Hello," + System.lineSeparator() + "there";
solution3
54 2016-06-28 13:41:49
Example
System.out.printf("I %n am %n a %n boy");
Output
I
am
a
boy
Explanation
It's better to use %n as an OS independent new-line character instead of \\n and it's easier than using System.lineSeparator()
Why to use %n , because on each OS, new line refers to a different set of character(s);
Unix and modern Mac's : LF (\n)
Windows : CR LF (\r\n)
Older Macintosh Systems : CR (\r)
LF is the acronym of Line Feed and CR is the acronym of Carriage Return . The escape characters are written inside the parenthesis. So on each OS, new line stands for something specific to the system. %n is OS agnostic, it is portable. It stands for \\n on Unix systems or \\r\\n on Windows systems and so on. Thus, Do not use \\n , instead use %n .
solution4
31 2013-04-22 05:58:50
It can be done several ways. I am mentioning 2 simple ways.
Very simple way as below:
System.out.println("I\\nam\\na\\nboy");It can also be done with concatenation as below:
System.out.println("I" + '\\n' + "am" + '\\n' + "a" + '\\n' + "boy");
solution5
15 2011-10-20 09:20:22
尝试：
System.out.println("I\nam\na\nboy");
solution6
13 2015-05-24 12:43:35
To make the code portable to any system, I would use:
public static String newline = System.getProperty("line.separator");
This is important because different OSs use different notations for newline: Windows uses "\\r\\n", Classic Mac uses "\\r", and Mac and Linux both use "\\n".
Commentors - please correct me if I'm wrong on this...
solution7
7 2015-07-31 07:29:07
\\n is used for making separate line;
Example:
System.out.print("I" +'\n'+ "am" +'\n'+ "a" +'\n'+ "boy");
Result:
I
am
a
boy
solution8
6 2011-10-20 09:21:24
If you simply want to print a newline in the console you can use ´\\n´ for newlines.
If you want to break text in swing components you can use html:
String s = "<html>first line<br />second line</html>";
solution9
5 2019-10-23 13:13:51
Platform-Independent Line Breaks:
finalString = "physical" + System.lineSeparator() + "distancing";
System.out.println(finalString);
Output:
physical
distancing
Notes:
- Java 6:
System.getProperty("line.separator") - Java 7 & above:
System.lineSeparator()
solution10
5 2011-10-20 09:25:46
If you want to have your code os-unspecific you should use println for each word
System.out.println("I");
System.out.println("am");
System.out.println("a");
System.out.println("boy");
because Windows uses "\\r\\n" as newline and unixoid systems use just "\\n"
println always uses the correct one
solution11
3 2015-07-30 21:58:03
What about %n using a formatter like String.format() ?:
String s = String.format("I%nam%na%nboy");
As this answer says, its available from java 1.5 and is another way to System.getProperty("line.separator") or System.lineSeparator() and, like this two, is OS independent .
solution12
1 2014-05-17 02:10:01
Full program example, with a fun twist:
Open a new blank document and save it as %yourJavaDirectory%/iAmABoy/iAmABoy.java . "iAmABoy" is the class name.
Paste the following code in and read through it. Remember, I'm a beginner, so I appreciate all feedback!
//The class name should be the same as your Java-file and directory name.
class iAmABoy {
//Create a variable number of String-type arguments, "strs"; this is a useful line of code worth memorizing.
public static void nlSeparated(String... strs) {
//Each argument is an str that is printed.
for (String str : strs) {
System.out.println(str);
}
}
public static void main(String[] args) {
//This loop uses 'args' . 'Args' can be accessed at runtime. The method declaration (above) uses 'str', but the method instances (as seen below) can take variables of any name in the place of 'str'.
for (String arg : args) {
nlSeparated(arg);
}
//This is a signature. ^^
System.out.print("\nThanks, Wolfpack08!");
}
}
Now, in terminal/cmd, browse to %yourJavaDirectory%/iAmABoy and type:
javac iAmABoy.java
java iAmABoy I am a boy
You can replace the args I am a boy with anything!
solution13
1 2016-02-10 10:24:01
Go for a split.
String string = "I am a boy";
for (String part : string.split(" ")) {
System.out.println(part);
}
solution14
0 2014-08-05 11:04:37
System.out.println("I\\nam\\na\\nboy");
This works It will give one space character also along before enter character
solution15
0 2018-09-30 05:30:14
I use this code String result = args[0].replace("\\\\n", "\\n");
public class HelloWorld {
public static void main(String[] args) {
String result = args[0].replace("\\n", "\n");
System.out.println(result);
}
}
with terminal I can use arg I\\\\nam\\\\na\\\\boy to make System.out.println print out
I
am
a
boy
solution16
0 2020-10-06 09:07:10
Here it is!! NewLine is known as CRLF (Carriage Return and Line Feed).
- For Linux and Mac, we can use "\\n".
- For Windows, we can use "\\r\\n".
Sample:
System.out.println("I\r\nam\r\na\r\nboy");
Result:
It worked for me.
solution17
0 2022-09-07 13:51:31
Best and easy approach is
"I\nam\na\nboy"
solution18
-1 2016-02-10 10:05:57
您可以在字符串中使用<br>标签以在 html 页面中显示
solution19
-1 2021-05-25 03:03:15
Here I am using the split function. I braked String from spaces. then I used println function and printed the value.
public class HelloWorld{
public static void main(String []args){
String input = "I am a boy";
String[] opuput = input.split(" ");
for (int i = 0; i < opuput.length; i++)
System.out.println(opuput[i]);
}
}
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