I have the following method to check allowed characters:
private boolean checkIfAllCharsAreValid(String test) {
boolean valid = false;
if (test.matches("^[a-zA-Z0-9,.;:-_'\\s]+$")) {
valid = true;
}
return valid;
}
but if test has the character -
in it the match return false. Do i have to escape the -
?
Inside [
... ]
the -
symbol is treated specially. (You use it yourself in this special purpose in the beginning of your expression where you have az
.)
You need to escape the -
character
[a-zA-Z0-9,.;:\-_'\s]
^
or put it last (or first) in the [...]
expression like
[a-zA-Z0-9,.;:_'\s-]
^
Some further notes:
Technically speaking all characters are valid in the empty string, so I would change from +
to *
in your expression.
String.matches
checks the full string, so the ^
and $
are redundant.
Your entire method could be wirtten as
return test.matches("[a-zA-Z0-9,.;:_'\\\\s-]*");
A -
in a character class surrounded on both sides is a regex meta character to denote range.
To list a literal -
in a char class you escape the -
in the char class:
if (test.matches("^[a-zA-Z0-9,.;:\\-_'\\s]+$"))
^^^
or place the -
at the end of char class:
if (test.matches("^[a-zA-Z0-9,.;:_'\\s-]+$"))
^
or place the -
at the beginning of char class:
if (test.matches("^[-a-zA-Z0-9,.;:_'\\s]+$"))
^
您可以将-
放在字符组的开头,以便它不会被解释为字符范围。
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