In C# how do i get the name of the running file?

Question

I would like to know how to pragmatically get the name of the running file not the assembly name but the name of the file in C# .NET,

I tried

System.Reflection.Assembly.GetEntryAssembly().GetName().Name

this gives the name of the assembly but i am looking for the name of the exe file instead.

Thank you!

Answer 1

 System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName

or

If you want the executable:

System.Reflection.Assembly.GetEntryAssembly().Location

If you'd like just the file*name* and not the path, use:

Path.GetFileName(System.Reflection.Assembly.GetEntryAssembly().Location)

Answer 2

System.Reflection.Assembly.GetEntryAssembly().Location

Answer 3

System.Windows.Forms.Application.ExecutablePath

"Gets the path for the executable file that started the application, including the executable name."

http://msdn.microsoft.com/en-us/library/system.windows.forms.application.executablepath.aspx

Answer 4

If you know your assembly is the EXE in which you are running (which I infer is likely, by the use of "GetEntryAssembly()"), you can use Process.GetCurrentProcess().ProcessName. This will return the name of the EXE for your program.

Answer 5

http://msdn.microsoft.com/en-us/library/system.environment.getcommandlineargs.aspx

Look at the first element in this array.

 System.Environment.GetCommandLineArgs()[0];

You can also look at args[0] in main(string args[])

This should change even if the program is renamed.

Answer 6

您可以使用：

System.Reflection.Assembly.GetExecutingAssembly().Location