I have writen this program:
#include <sstream>
#include <math.h>
#include <string>
#include <vector>
using namespace std;
double distance(vector<double> *, vector<double> *, int);
const char* distances(vector<vector<double>* >, int);
double distance(vector<double> a, vector<double> b){
double result = 0, di;
for(int i=0;i<a.size();i++){
di = a[i] - b[i];
result += di*di;
}
return sqrt(result);
}
const char* distances(vector<vector<double>* > vectors, int accuracy=1){
stringstream graphstr;
graphstr << "strict graph {\n";
for(int i=0; i<vectors.size();i++){
int j=i+1;
while(j<vectors.size()){
graphstr << "\t" << i << " -- " << j << "\t [len=" << distance(vectors[i],vectors[j]) << "];\n";
j+=accuracy;
}
}
graphstr << "}\n";
return graphstr.str().c_str();
}
and when the vectors.size()
is greather than 70 it gives me a segmentation fault. what is the problem?
when I not adding new stings to graphstr
it is OK.
您将返回指向在函数出口处释放的字符串的指针。
Try this
Change your return value from const char* to char* and
char* buff = new char[4096];
strcpy(buff,graphstr.str().c_str(),graphstr.str().size());
return buff;
Remember to free the memory returned using delete
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