The topic is confusing, however for example,
final String pattern = "(abc)";
final String content = "dabcef";
Matcher m = Pattern.compile(pattern).matcher(content);
The m.find() will surely return true.
I want to know if it's possible to process chars only once, meaning
"dab" -> not found, "cef" -> not found, over.
Thanks!
EDIT:
Actually I want to find all matches instead of only check if matches or not. For example,
abc abc def abc dab cef (actually without spaces)
will be matched by ^(.{3})*?(abc), however only once. And I expect 3 matches.
Thanks!
怎么样:
final String pattern = "^(.{3})*(abc)";
I found the solution by moving start index. Thank @Oil for the suggestion!
public static void main(String[] args) {
final String pattern1 = "^(.{3})*?(abc)";
final String content1 = "efabcabcdabcefaabcdfabce"; // two matches
final String content2 = "abcabcdabcefabc"; // three matches
Matcher mStart = Pattern.compile(pattern1).matcher(content1);
while (mStart.find()) {
System.out.println(mStart.group(mStart.groupCount()));
System.out.println(mStart.start() + ", " + mStart.end());
mStart = mStart.region(mStart.end(), mStart.regionEnd());
}
//-----------------------------
System.out.println("------------------------");
mStart = Pattern.compile(pattern1).matcher(content2);
while (mStart.find()) {
System.out.println(mStart.group(mStart.groupCount()));
System.out.println(mStart.start() + ", " + mStart.end());
mStart = mStart.region(mStart.end(), mStart.regionEnd());
}
}
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