How do I replace the last character in a string with VB6?
Question
How do I replace the last character in a string with VB6? I've got the syntax
Replace$(expression, find, replacewith[, start[, count[, compare]]])
but I can't seem to find the right use of it. I've got something like
iLength = Len(sBuild)
sBuild = Replace(sBuild, "^", "ú", iLength, 1)
This isn't working but I can't seem to find any examples online.
Thanks!
2 answers
solution1
10 2012-01-18 00:24:00
Another method is to use the Mid() keyword:
Mid$(sBuild, Len(sBuild), 1) = "ú"
This also has the advantage of not doing string concatenation/memory reallocation.
solution2
4 ACCPTED 2012-01-17 18:22:40
尝试
sBuild = Left$(sBuild, iLength - 1) & "ú"
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