Would something like:
classname* p = new classname(parameter1, parameter2, ...);
create a pointer that points to an object initialized using a non-default constructor with signature: classname(parameter1, parameter2, ...)
?
Thanks!
对,那是正确的。
我自己不能放得更好-记住要在完成后删除它,除非您想让堆不开心!
Yes, it will. This program illustrates the concept.
#include <string>
#include <iostream>
class Foo
{
private:
std::string name;
public:
Foo() : name("default"){}
Foo(std::string Name): name(Name) {}
void Print() { std::cout << name << std::endl; }
};
int main ()
{
Foo* foo = new Foo();
foo->Print();
delete foo;
foo = new Foo("special");
foo->Print();
delete foo;
}
The output is:
default
special
Yes it does. but may I know how did the question came to your mind? you got some errors?
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