I have string of the following form:
भन्ने [-0.4531954191090929, 0.7931147934270654, -0.3875088408737827, -0.09427394940704822, 0.10065554475134718, -0.22044284832864797, 0.3532556916833505, -1.8256229909222224, 0.8036832111904731, 0.3395868096795993]
Whereever [ or ] or ,
char are present , I just want to remove them and i want each of the word and float separated by a space. It is follows:
भन्ने -0.4531954191090929 0.7931147934270654 -0.3875088408737827 -0.09427394940704822 0.10065554475134718 -0.22044284832864797 0.3532556916833505 -1.8256229909222224 0.8036832111904731 0.3395868096795993
I am representing each of these string as line
. i did following:
line.replaceAll("([|]|,)$", " ");
But it didn't work for me. There was nothing change in the input line. Any help is really appreciated.
Strings are immutable. Try
line = line.replaceAll("([|]|,)$", " ");
Or to be a bit more verbose, but avoiding regular expressions:
char subst = ' ';
line = line.replace('[', subst).replace(']', subst).replace(',', subst);
In Java, strings are immutable , meaning that the contents of a string never change. So, calling
line.replaceAll("([|]|,)$", " ");
won't change the contents of line
, but will return a new string. You need to assign the result of the method call to a variable. For instance, if you don't care about the original line
, you can write
line = line.replaceAll("([|]|,)$", " ");
to get the effect you originally expected.
[
and ]
are special characters in a regular expression. replaceAll is expected a regular expression as its first input, so you have to escape them.
String result = line.replaceAll("[\\[\\],]", " ");
Cannot tell what you were trying to do with your original regex, why you had the $ there etc, would need to understand what you were expecting the things you put there to do.
Try
line = "asdf [foo, bar, baz]".replaceAll("(\\[|\\]|,)", "");
The regex syntax uses []
to define groups like [az]
so you have to mask them.
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